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Personally, I've been training squirrel monkeys to exchange tokens for food and one of them has finally learned it.
2 years agoCaseyE
In the RWBY Facebook Q&A, Miles and Kerry said that "Dog Faunus + Dog Faunus = Dog Faunus, Dog Faunus + Human = Either Dog Faunus or Human, Dog Faunus + Cat Faunus = Random Faunus." From this we could say that whether you're a faunus or a human is determined by either a dominant or recessive allele - it doesn't seem to matter which, so we'll say humanity is recessive - and whether you're a cat or a dog faunus is determined by a dominant allele.
Time to draw some Punnett squares, kids.
Let's say F is faunus, and f is human. So if both parents are FF (faunus), all their possible kids will be FF (faunus). Faunus + Faunus = Faunus. So far, so good.
They say that Human + Faunus = either Human or Faunus. If one parent is FF and one is Ff (faunus but carrying the recessive human trait), 50% of their possible kids would be FF and 50% would be Ff. This is still Faunus + Faunus = Faunus. If one parent is FF and one is ff (human), their kids have a 50% chance of being FF and a 50% chance of being Ff. This is Human + Faunus = Faunus; still within the rules. If both parents are Ff, their kids have a 50% chance of being Ff and a 50% chance of being ff. Human + Faunus = Human or Faunus. We're still good! And of course, if both parents are ff, their kids have a 100% chance of being ff. Human + Human = Human.
Again, it works both ways with humanity as either the recessive or
the dominant trait, but I decided to knock it off its high horse and
make it recessive.
Now we move on to figuring out how Faunus end up with specific animal traits.
For this, it seems like we may need to say that all Faunus traits are homozygous dominant - are all DD or CC, no Dd or Cc or even dd.
So if both parents are DD (dog), their possible children are all DD (dog). Dog Faunus + Dog Faunus = Dog Faunus.
If one parent is DD and one parent is CC (cat), their possible children are all DC. This is a case of two different dominant alleles being represented at the same time - like when a rabbit has both black and white fur. In this case it would seem like the person would have both dog and cat traits - but we're told it would produce a "random faunus." So maybe one of the traits would have to win out over the other? This would be solved if one of the parents was heterozygous - was Dd or Cc, with the little letter being a recessive allele. But if that happened, there's a 25% chance of a kid having dc, two recessive traits, and they would both be expressed - but what is the recessive trait here? Being born to two Faunus parents but not having any animal traits? Is that like being a Squib? Maybe the recessive trait is a specific different animal that is also coded for by its own dominant allele, like D is dog and B is bird, but b is also dog? That way you could end up with a seemingly random Faunus. So Dog Faunus + Cat Faunus = either Dog Faunus, Cat Faunus, or "Random" Faunus, depending on how you want to handle the alleles.
Now, Blake and Tukson are both feline Faunus, but Tukson is alluded to as being "some kind of panther," while Blake seems to be more like a domestic shorthair cat. Blake's only physical cat trait seems to be the ears. Tukson's only visible trait seems to be his claws. Is this because they are different species of cat faunus, and therefore different sets of genes are being expressed? Can we then assume that all domestic cat Faunus only have ears, and all panther Faunus only have claws? Or is the actual expression of your animal traits random or determined by your parentage? Maybe Blake's mother had a dominant allele for ears, and her father had a recessive allele for claws, so she ended up with only ears (Ee).
Or maybe it’s just fucking magic.
3 years agoCaseyE
2018 years agoCaseyE
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